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The length of the seconds hand of a watch is 10 mm. What is the change in the angular speed of the watch after 15 seconds (in rad s^-1)

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Zero

$\frac{\sqrt{2} π}{3000}$

$\frac{π}{60}$

$10 \sqrt{2}$

answer is A.

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Detailed Solution

Angular speed of seconds hand of watch is constant and equal to $\frac{2 π}{60} \frac{rad}{\sec} = \frac{π}{30} rad / \sec .$ So change in angular speed will be zero

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