The length of the shadow of a stick of height 1 meter, when the angle of elevation of the sun is 60^o, will be _______.

Let (AB - 1) cm be the stick.

Let AC be the shadow of length x.

from right-angled $∆\mathrm{ACB}$,

$\tan 60°=\frac{1}{\mathrm{x}}$

or $\sqrt{3}=\frac{1}{\mathrm{x}}$

or $\mathrm{x}=\frac{1}{\sqrt{3}} \mathrm{m}$

Thus, the length of the shadow = $\frac{1}{\sqrt{3}}$m