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The length of the two rods made up of the same metal and having the same area of cross-section are 0.6 m and 0.8 m respectively. The temperature between the ends of first rod is $90^{\circ} C$ and $60^{\circ} C$ and that for the other rod is $150^{\circ} C$ and $110^{\circ} C$ . For which rod the rate of conduction will be greater

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First

Second

Same for both

None of the above

answer is C.

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Detailed Solution

$\frac{Q_{1}}{t} = \frac{K A (90 - 60)}{0.6} = 50 KA and \frac{Q_{2}}{t} = \frac{KA (150 - 110)}{0.8} = 50 KA$

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