The level of water in a tank is 5 m high. A hole of area 1 cm2 is made at the bottom of the tank. The rate of leakage of water from the hole is (Take, g = 10 ms-2)

Rate of leakage of water from the hole =Av=A2gh=10−42×10×5=10−3m3s−1

Rate of leakage of water from the hole =Av=A2gh=10−42×10×5=10−3m3s−1

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The level of water in a tank is 5 m high. A hole of area 1 cm² is made at the bottom of the tank. The rate of leakage of water from the hole is (Take, g = 10 ms^-2)

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$10^{- 3} m^{3} s^{- 1}$

$10^{- 4} m^{3} s^{- 1}$

$10 m^{3} s^{- 1}$

$10^{- 2} m^{3} s^{- 1}$

answer is A.

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Rate of leakage of water from the hole

$= A v = A \sqrt{2 g h}$

$= 10^{- 4} \sqrt{2 \times 10 \times 5} = 10^{- 3} m^{3} s^{- 1}$

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