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The limiting molar conductivities of a divalent cation $(M^{2 +})$ And a monovalent anion $(A^{-})$ are $57 S {cm}^{2} {mol}^{- 1}$ and $73 S {cm}^{2} {mol}^{- 1}$ Respectively. Then find the limiting molar conductivity shown by their compound in $S {cm}^{2} {mol}^{- 1}$ .

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187

203

130

302

answer is B.

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Detailed Solution

Formula of the substance MA₂

$\overset{0}{Λ} M A_{2} = \overset{0}{Λ} M^{+ 2} + 2 \times {\overset{0}{Λ}}_{M} A^{-}$

= 57+2x73 = 203

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