The line integral of the magnetic induction field around any closed path is equal to

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$∮ \vec{B} \cdot \vec{dl} = μ_{0}$

$∮ \vec{B} \cdot \vec{dl} = μ_{0} I_{enclosed}$

$∮ \vec{B} \cdot \vec{dl} = μ_{0} {(I_{enclosed})}^{2}$

$∮ \vec{B} \cdot \vec{dl} = \frac{μ_{0}}{(I_{enclosed})}$

answer is A.

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Detailed Solution

From Ampere’s Circuital Law

Line integral to the magnetic field of the coil = μ_otimes the current passing through it. It is mathematically expressed as

$∮ \vec{B} \cdot \vec{dl} = μ_{0} I_{enclosed}$

Here μ₀ = permeability of free space = 4 π × 10^-15 N/ A² and

∫ B.dl = line integral of B around a closed path.

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