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Q.

 The line x+y+1=0 is an asymptote of x2y2+xy2=0. The other asymptote is 

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a

x + y = 0

b

x - y = 0

c

x - y = 1

d

x - y + 1 = 0

answer is B.

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Detailed Solution

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Given hyperbola x2-y2+x-y-2=0 This is rectangular hyperbola  centre =(-12,-12) Given one asymptote is x+y+1=0

since for rectangular hyperbola asymptotes are perpendicular then

Other asymptote of rectangular hyperbola  is x-y=k It passes through the poinyt (-12,-12) then k=0 so required asymptote is x-y=0

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