Q.

The line 21x + 5y = λ touches the hyperbola 7x2  5y2 = 232 then λ=

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a

232

b

110

c

58

d

116

answer is A.

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Detailed Solution

Given hyperbola is x22327-y22325=1

Given tangent 21x+5y-λ=0

Apply tangent condition n2=a2l2-b2m2 λ2=2327(21)2-2325(5)2 λ2=232[63-5] λ=232×58 λ=116×116 λ=116

 

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