The linear equation $x = 9$ in two variables can be written as

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$1 \cdot x + 0 \cdot y + (- 9) = 0$

$1 \cdot x + 1 \cdot y + (- 9) = 0$

$1 \times x + 9 = 10$

$0 . x + 1 \cdot y + (- 9) = 0$

answer is A.

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Detailed Solution

If an equation is written in the form $a x + b y + c = 0$ it is said to be a linear equation in two variables, where a, b, and c are real integers and the coefficients of x and y, i.e. a and b are not equal to zero.
It is given that the equation is $x = 9$
It can be written as,
$\Rightarrow x - 9 = 0 \Rightarrow 1 . x + (- 9) = 0$
$\Rightarrow 1 \cdot x + 0 \cdot y + (- 9) = 0$ , which is in the form of $a x + b y + c - 0$
which is in the form of $a x + b y + c - 0$
Thus, the linear equation $x = 9$ in two variables can be written as $1 . x + 0 . y + (- 9) = 0 .$