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Q.

The lines whose direction cosines are given by the relations al + bm + cn = 0 and nm + nl + lm = 0 are

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a

perpemdicular if 1a+1b+1c=0

b

parallel if a+b+c=0

c

perpendicular if a+b+c=0

d

parallel if 1a+1b+1c=0

answer is A.

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Detailed Solution

al+bm+cn=0  l=-(bm+cn)a lm+mn+nl=0 -(bm+cn)am+mn-nbm+cna=0 -bm2-cmn+amn-bmn-cn2=0 bmn2-(a-b-c)mn+c=0

m1n1, m2n2  are roots of eqn

m1n1·m2n2=cb m=-(al+cn)b lm+mn+nl=0 -l(al+cn)b+ln-(al+cn)bn=0 al2+cln-bln+aln+cn2=0 aln2+(a-b+c)ln+c=0

l1n1, l2n2 are roots of eqn.

l1 l2n1 n2=cal1 l2n1 n2+m1 m2n1 n2+1=0l1 l2+m1 m2+n1 n2=0

lines are er

ca+cb+1=0  1a+1b+1c=0

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