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The lines $\frac{x - 1}{1} = \frac{y + 1}{- 1} = \frac{z}{2} and \frac{x}{2} = \frac{y - 1}{- 2} = \frac{z - 1}{λ}$ are
LIST – I LIST – II
A) Parallel i) $λ = - 2$
B) Perpendicular ii) $λ = 4$
C) Coplanar iii) $λ = 5$
D) Skew lines iv) $λ = 9$

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$A \to 1, B \to 2, C \to 4, d \to 3$

$A \to 2, B \to 1, C \to 2, d \to 3$

$A \to 4, B \to 1, C \to 3, d \to 2$

$A \to 2, B \to 1, C \to 3, d \to 2$

answer is B.

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Detailed Solution

Parallel $\to \frac{2}{1} = \frac{- 2}{- 1} = \frac{λ}{2}$
Perpendicular →2+2+2λ=0
Since λ=4, parallel → they are coplanar
For λ=5, AB. $({\bar{n}}_{1} \times {\bar{n}}_{2}) \neq 0$
$\Rightarrow$ They are skew lines

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