Q.

 The line xayb=1 meets the x-axis at P. Find the equation of line perpenducular to the line at P.

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Detailed Solution

Given line xayb=1 bxay=ab(1)
It meets the x-axis then  y=0
 from (1)bx=abx=a
P=(a,0)
Equation of line perpendicular to equation (1) and Passing through (a, 0) is ax + by + k = 0 .... (2)
sub(a,0) a(a)+0+k=0 k=a2
 from (2) ax+bya2=0

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