The liquids shown in fig. in the two arms are mercury (specific gravity =13.6) and water. If the difference of heights of the mercury columns is 2 cm, find the height h of the water column.

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27 cm

30 cm

35 cm

40 cm

answer is A.

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Detailed Solution

$\begin{array}{l} \frac{ρ_{Hg}}{ρ_{w}} = 13 .6 \\ P = ρgh; ρ \propto \frac{1}{h} \\ \frac{ρ_{Hg}}{ρ_{w}} = \frac{h_{w}}{h_{h g}} \Rightarrow 13 .6 = \frac{h_{w}}{2} \\ h_{w} = 27 .2 cm = 27 cm \end{array}$ Question Image

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