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The liquids shown in figure in the arms are mercury (Specific gravity = 13.6) and water. If the different of heights of the mercury columns is 2 cm, then the height of the water column is

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30 cm

72 cm

27 cm

32 cm

answer is D.

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Detailed Solution

$P_{A} = P_{B}$

$h_{1} ρ_{1} = h_{2} ρ_{2}$

$h_{1} \times 1 = 2 \times 13.6$

$h_{1} = 27.2 cm \approx 27 cm$

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