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The locus of a point which divides the join of A (-1,1) and a variable point P on the circle $x^{2} + y^{2} = 4$ in the ratio $3 : 2$ is

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$25 (x^{2} + y^{2}) + 20 (x + y) + 28 = 0$

$25 (x^{2} + y^{2}) - 20 (x + y) + 28 = 0$

$25 (x^{2} + y^{2}) + 20 (x - y) + 28 = 0$

$25 (x^{2} + y^{2}) + 20 (x - y) - 28 = 0$

answer is D.

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Detailed Solution

$(x, y) = (\frac{3 α - 2}{5}, \frac{3 β + 2}{5}) β = \frac{5 y - 2}{3} \Rightarrow (α, β) lies on x^{2} + y^{2} = 4$

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