Q.

The locus of midpoint of focal chords of the parabola y2=4ax is

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

y2=a(2xa)

b

y2=2a(xa)

c

y2=2a(x+a)

d

y2=a(2x+a)

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Given parabola y2=4axlet P(x1,y1) be locus of mid pointEquation of chord is S1=S11yy1-2a(x+x1)=y21-4ax1it passes through (a,0) theny12=2ax-2a2locus is y2=2a(x-a)y2=2a(xa)  

Watch 3-min video & get full concept clarity

tricks from toppers of Infinity Learn

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon