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Q.

The locus of midpoints of chords of the circle x2+y2-2px=0, passing through the origin is 

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a

x2+y2+px=0

b

x2+y2-4px=0

c

x2+y2-px=0

d

x2+y2+2px=0

answer is B.

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Detailed Solution

Let Px1, y1 be a point on the locus.

Equation of the chord of the circle x2+y2-2px=0having Px1, y1 as midpoint is S1=S11

xx1+yy1-px+x1=x12+y122px1x1px+y1y=x12+y12px1

This passes through the origin 0, 0x1-p0+y10=x12+y12px1x12+y12px1=0

Locus of x1, y1 is x2+y2-px=0.

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