Q.

The locus of midpoints of chords of the circle x2+y2-2px=0, passing through the origin is 

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

x2+y2+px=0

b

x2+y2-4px=0

c

x2+y2-px=0

d

x2+y2+2px=0

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Let Px1, y1 be a point on the locus.

Equation of the chord of the circle x2+y2-2px=0having Px1, y1 as midpoint is S1=S11

xx1+yy1-px+x1=x12+y122px1x1px+y1y=x12+y12px1

This passes through the origin 0, 0x1-p0+y10=x12+y12px1x12+y12px1=0

Locus of x1, y1 is x2+y2-px=0.

Watch 3-min video & get full concept clarity

tricks from toppers of Infinity Learn

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon