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Q.

The locus of P such that the area of ΔPQR is 12 sq.units where Q2, 2 and R4,5 is

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a

x26xy+9y2+22x+66y+23=0

b

x2+4y2+4xy12x24y28=0

c

x2+5xy+9y2+20x+62y+22=0

d

x2+6xy+9y222x66y23=0

answer is D.

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Detailed Solution

P(x,y),Q(2,2),R(4,5)PQR=1212x2x+4y2y5=12|(x2)(y5)(x+4)(y2)|=24|x+2y6|=8|x+2y6|=8x2+4y2+4xy12x24y28=0

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