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Q.

The locus of point of intersection of perpendicular tangents drawn to y2=4ax is

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a

x=a

b

x=0

c

x+a=0

d

y=0

answer is C.

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Detailed Solution

y2=4ax

The slope form of tangent to the parabola is y=mx+am

This can be writte as

my-m2x-a=0m2x-my+a=0

If this is passing  through the point x1,y1 then 

m2x1-my1+a=0

The product of the slopes is m1m2=ax1

The locus of point of intersection of tangents which are pependicular is m1m2=-1

ax1=-ax1+a=0

Perpendicular tangents intersect on a directrix whose equations is x+a=0

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