Q.

The locus of the point of intersection of the tangents to the circle  x2+y2=a2, which include an angle of  450 is the curve x2+y2=λa2. The value of  λ equals to (where . denotes G.I.F)
 

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a

2

b

16

c

6

d

4

answer is C.

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Detailed Solution

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tanθ2=rS11 tan45°2=ax12+y12-a2 locus of x1,y1 is x2+y2=a24+8

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