The $\log \lambda vs\log E$ graph between energy E of an electron and its de-Broglie wavelength $\lambda$ will be

We know that if the mass of the electron is m and the energy of  the electron is E then the De Brogile wavelength of  the electron is  given by   $\lambda =\frac{h}{\sqrt{2mE}}$
By applying logarithm ,we get log  $\lambda =\log \left[\frac{h}{\sqrt{2mE}}\right]$
$\log \lambda =\log h-\log \sqrt{2mE}$
.$\Rightarrow \log \lambda =\log \left[\frac{h}{\sqrt{2m}}\right]-\frac{1}{2}\log E$
$\Rightarrow$ The graph bêtween log $\lambda$  and log E is a straight line with a negative slope and positive Y-intercept