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Q.

The longest wavelength of the Lyman series to Hydrogen atom is the same as the wavelength of certain line in the spectrum of He+ when the electron makes a transition from n→2 The value of n is:

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a

6

b

3

c

4

d

5

answer is B.

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Detailed Solution

According to the question,

λHe+ =

=RHZHe+2122−142

Z = Atomic number of He

112−122 =22122−1n2 ⇒n=4

 

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