The loop ABCDEFGH, shown in figure, is carries a current i. A uniform magnetic field B→ exists in that region of space as shown in figure. Then magnetic torque experienced by the loop is, [Given, AB = BC = CD =l and EF = FG = GH = l/2]

Magnetic dipole moment, of the loop, M=l2-l22i=3l2i4 and it is inward. ∴τ=MBsin90o=3i l2B4

The loop ABCDEFGH, shown in figure, is carries a current i. A uniform magnetic field B→ exists in that region of space as shown in figure. Then magnetic torque experienced by the loop is, [Given, AB = BC = CD =l and EF = FG = GH = l/2]

Magnetic dipole moment, of the loop, M=l2-l22i=3l2i4 and it is inward. ∴τ=MBsin90o=3i l2B4

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The loop ABCDEFGH, shown in figure, is carries a current i. A uniform magnetic field $\vec{B}$ exists in that region of space as shown in figure. Then magnetic torque experienced by the loop is,
[Given, AB = BC = CD =l and EF = FG = GH = l/2]

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$\frac{1}{4} i l^{2} B$

$\frac{3}{8} i l^{2} B$

$\frac{1}{2} i l^{2} B$

$\frac{3 i l^{2} B}{4}$

answer is C.

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Detailed Solution

Magnetic dipole moment, of the loop, $M = [l^{2} - {(\frac{l}{2})}^{2}] i = \frac{3 l^{2} i}{4}$ and it is inward.

$∴ τ = MBsin 90^{o} = \frac{3 i l^{2} B}{4}$

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The loop ABCDEFGH, shown in figure, is carries a current i. A uniform magnetic field B→ exists in that region of space as shown in figure. Then magnetic torque experienced by the loop is, [Given, AB = BC = CD =l and EF = FG = GH = l/2]

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The loop ABCDEFGH, shown in figure, is carries a current i. A uniform magnetic field $\vec{B}$ exists in that region of space as shown in figure. Then magnetic torque experienced by the loop is,
[Given, AB = BC = CD =l and EF = FG = GH = l/2]