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The lower end a capillary tube of diameter 2.00 mm is dipped in water 8 cm below the surface in a beaker it so that an air bubble is formed at the end of the tube inside water. The excess pressure inside the bubble will be (in Pascal) (T = 73 dyne/ cm)

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An Intiative by Sri Chaitanya

1.0193 x 10⁵

1.02 x 10⁴

146

1.078 x 10⁵

answer is A.

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Detailed Solution

$\large P_{excess}=\frac {2T}{r}=\frac {2\times 73\times 10^{-3}}{\left ( \frac 22\times 10^{-3} \right )}=146Pa$

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