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The lowest term of $161207$ is ____.

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Detailed Solution

The lowest term of

161207

79 .

Given two numbers are 161 and 207.
To reduce the fraction into its lowest form, divide the numbers by their HCF.

161 = 7 × 23 207 = 3 × 3 × 23

Therefore, the HCF of 161 and 207 = 23.
Now,

16123 = 7 and 20723 = 9

Therefore the lowest term of

161207

79 .

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