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The magnet supended in uniform magnetic field is heated so as to reduce its magnetic moment by 19%. By doing this, the time period of the magnet will

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decreases by 4%

decreases by 19%

increases by 19%

increases by 11%

answer is A.

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Detailed Solution

$\begin{array}{l} \frac{T_{2}}{T_{1}} = \sqrt{\frac{M_{1}}{M_{2}}} = \sqrt{\frac{100}{81}} = \frac{10}{9} \\ \frac{T_{2} - T_{1}}{T_{1}} \times 100 = (\frac{10 - 9}{9}) \times 100 = 11 % increases \end{array}$

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