The magnetic field at a distance x on the axis of a circular coil of radius R is 18th of that at the centre. The value of x is

Bx=18Bc ∴μ0NiR22R2+x232=18μ0Ni2R

The magnetic field at a distance x on the axis of a circular coil of radius R is 18th of that at the centre. The value of x is

Bx=18Bc ∴μ0NiR22R2+x232=18μ0Ni2R

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The magnetic field at a distance x on the axis of a circular coil of radius $R$ is $\frac{1}{8}$ th of that at the centre. The value of x is

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$\frac{R}{\sqrt{3}}$

$\frac{2 R}{\sqrt{3}}$

$R \sqrt{3}$

$R \sqrt{2}$

answer is C.

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$B_{x} = \frac{1}{8} B_{c} ∴ \frac{μ_{0} N i R^{2}}{2 {(R^{2} + x^{2})}^{\frac{3}{2}}} = \frac{1}{8} [\frac{μ_{0} N i}{2 R}]$

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The magnetic field at a distance x on the axis of a circular coil of radius R is 18th of that at the centre. The value of x is

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The magnetic field at a distance x on the axis of a circular coil of radius $R$ is $\frac{1}{8}$ th of that at the centre. The value of x is