Q.

The magnetic field at all points within the cylindrical region whose cross-section is indicated in the accompanying figure start increasing at a constant rate α T/s. Find the magnitude of electric field as a function of , the distance from the geometric centre of the region.

see full answer

Want to Fund your own JEE / NEET / Foundation preparation ??

Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*
An Intiative by Sri Chaitanya

a

for rR, E=rα2; for rR, E=αR22r

b

for rR, E=α2; for rR, E=αR2r

c

for rR, E=α2; for rR, E=R22r

d

for rR, E=r2; for rR, E=α2r

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

For rR

Using El=SdBdt or E(2πr)=(πr2)α

The magnetic field at all points within the cyllindrical region whose cross  section is indicated in the accompanying Figure starts increasing at a constant  rate alpha. T//s. find the magnitud of electric

E=rα2

Er, i.e. E-r graph is a straight line passing through origin.

At r=RE=Rα2

For rR

The magnetic field at all points within the cyllindrical region whose cross  section is indicated in the accompanying Figure starts increasing at a constant  rate alpha. T//s. find the magnitud of electric

Using El=SdBdt,

E(2πr)=(πR2)α E=αR22r

E1r, i.e. E-r graph is a rectangular hyperbola.

The E-r graph is as shown in figure.

The magnetic field at all points within the cyllindrical region whose cross  section is indicated in the accompanying Figure starts increasing at a constant  rate alpha. T//s. find the magnitud of electric

The direction of electric field is shown in above figure.

Watch 3-min video & get full concept clarity
AITS_Test_Package
AITS_Test_Package
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon