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The magnetic field B₀ due to a current carrying circular loop of radius 12 cm at its centre is 0.50 × 10^-4 T. The magnetic field due to this loop at a point on the axis at a distance of 5 cm from the centre is :

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5.3 × 10^-9 T

3.9 × 10^-5 T

9.3 × 10^-5 T

3.5 × 10^-9 T

answer is D.

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Detailed Solution

$B_{A} = \frac{B_{C}}{{(1 + \frac{x^{2}}{r^{2}})}^{3 / 2}}$

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