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Q.

The magnetic field due to a semi circular wire of radius 10 cm carrying a current of 5A at its centre of curvature is

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a

$3.6 \times 10^{- 5} T$

b

$1.8 \times 10^{- 5} T$

c

$1.6 \times 10^{- 5} T$

d

$3.2 \times 10^{- 5} T$

answer is A.

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Detailed Solution

$B = \frac{μ_{0} I}{4 r}$

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