The magnetic field due to a straight current-carrying wire is:

Magnetic field due to a straight current-carrying conductor is directly proportional to the current in the wire

In Biot- Savart Law

Magnetic field 'B' at a radial distance 'r', due to a wire-carrying current is given by:

$B=\frac{{\mu }_{o}I}{2\pi r}$

Where '${\mu }_o$' is the permeability of free space $\left(4\pi \times {10}^{-7}\mathrm{Tm}/\mathrm{A}\right)$, and 'I' is the current.

Magnetic field intensity, $B=\frac{{\mu }_{o}I}{2\pi r}$

$\Rightarrow B\propto I$

Thus, the magnetic field is directly proportional to the current in the wire.