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Q.

The magnetic field energy in an inductor changes from maximum value to minimum value in 5.0 ms when connected to an AC source. The frequency of the source is

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a

200Hz

b

500Hz

c

20Hz

d

50Hz

answer is B.

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Detailed Solution

magnetic field energy decreases from maximum to minimum the change in phase is $\frac{π}{2}$
$ωt = \frac{π}{2};$

$2 πf \times 5 \times 10^{- 3} = π / 2$

$f = 50 Hz$

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