The magnetic field in a plane EM wave is given by- B=(100 μT)sin[(2×1015s−1)(t−x/c)]j^The equation for electric field is-

E = 100 μN / C sin [ ( 2 × 10 15 s − 1 ) ( t − x/c ) ] k ^

E = 100 μN / C sin [ ( 2 × 10 15 s − 1 ) ( t − x/c ) ] k ^

E = 3 × 10 10 μN/C sin 2 × 10 15 s − 1 t − x/c − j ^

E = 100 μN / C sin [ ( 2 × 10 15 s − 1 ) ( t − x/c ) ] ( − k ^ )

E = 100 μN / C sin [ ( 2 × 10 15 s − 1 ) ( t − x/c ) ] k ^

E = 3 × 10 10 μN/C sin [ ( 2 × 10 15 s − 1 ) ( t − x/c ) ] - k ^

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The magnetic field in a plane EM wave is given by- $B = (100 μT) \sin [(2 \times 10^{15} s^{- 1}) (t - x/c)] \hat{j}$
The equation for electric field is-

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$E = 3 \times 10^{10} μN/C \sin [(2 \times 10^{15} s^{- 1}) (t - x/c)] (- \hat{j})$

$E = 100 μN / C \sin [(2 \times 10^{15} s^{- 1}) (t - x/c)] (- \hat{k})$

$E = 100 μN / C \sin [(2 \times 10^{15} s^{- 1}) (t - x/c)] \hat{k}$

$E = 3 \times 10^{10} μN/C \sin [(2 \times 10^{15} s^{- 1}) (t - x/c)] (- \hat{k})$

answer is C.

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$E_{0} = c B_{0} = 3 \times 10^{8} \times 100 \times 10^{- 6} = 3 \times 10^{10} μ N / C$

As the wave is progressing in x-direction and the magnetic field is in y-direction, the electric field will be along -z direction.

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