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Q.

The magnetic field, of a given length of wire for single turn coil, at its center is ‘B’ then its value for two turns coil for the same wire is

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a

4B

b

B4

c

B2

d

2B

answer is C.

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Detailed Solution

B=μnI2a

For first turn L=2πa,a=L2π

If number of turns becomes twice, then 

4πr=L

r=L4π=a2,n=2,r=a2

B'=μ2I2⋅a2=4B

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