The magnetic field of a plane electromagnetic wave in a substance given by B=2×10−7sin(400x+1.6×1010t) . Speed of the electromagnetic wave is ____×107ms−1

Comparing the given equation with the standard wave equation B=B0sin⁡(kx+wt) we have ω=1.6×1010rad−1,K=400m−1V=ωk=1.6×1010400=16×10164000=4×107ms−1

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The magnetic field of a plane electromagnetic wave in a substance given by $B = 2 \times 10^{- 7} \sin (400 x + 1.6 \times 10^{10} t)$ . Speed of the electromagnetic wave is $____\times 10^{7} m s^{- 1}$

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Comparing the given equation with the standard wave equation $B = B_{0} \sin (kx + wt)$

we have $ω = 1.6 \times 10^{10} {rad}^{- 1}, K = 400 m^{- 1}$

$V = \frac{ω}{k} = \frac{1.6 \times 10^{10}}{400} = \frac{16 \times 10^{16}}{4000} = 4 \times 10^{7} {ms}^{- 1}$

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