The magnetic field of a plane-polarized electromagnetic wave moving in the z-direction is given by B=1.2×10−6sin[2π(z240−107t8)] in SI units. What is the maximum electric field ?

EoBo=v⇒E0=vB0 E0=2π[1078](2π240)×1.2×10−6 E0=3×108×1.2×10−6 =3.6×102=360V/m

The magnetic field of a plane-polarized electromagnetic wave moving in the z-direction is given by B=1.2×10−6sin[2π(z240−107t8)] in SI units. What is the maximum electric field ?

EoBo=v⇒E0=vB0 E0=2π[1078](2π240)×1.2×10−6 E0=3×108×1.2×10−6 =3.6×102=360V/m

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The magnetic field of a plane-polarized electromagnetic wave moving in the z-direction is given by $B = 1.2 \times 10^{- 6} \sin [2 π (\frac{z}{240} - \frac{10^{7} t}{8})]$ in SI units. What is the maximum electric field ?

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1000 V/m

180 V/m

81 V/m

360 V/m

answer is D.

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$\frac{E_{o}}{B_{o}} = v \Rightarrow E_{0} = v B_{0}$

$E_{0} = \frac{2 π [\frac{10^{7}}{8}]}{(\frac{2 π}{240})} \times 1.2 \times 10^{- 6}$

$E_{0} = 3 \times 10^{8} \times 1.2 \times 10^{- 6}$

$= 3.6 \times 10^{2} = 360 V / m$

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The magnetic field of a plane-polarized electromagnetic wave moving in the z-direction is given by B=1.2×10−6sin[2π(z240−107t8)] in SI units. What is the maximum electric field ?

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The magnetic field of a plane-polarized electromagnetic wave moving in the z-direction is given by $B = 1.2 \times 10^{- 6} \sin [2 π (\frac{z}{240} - \frac{10^{7} t}{8})]$ in SI units. What is the maximum electric field ?