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Q.

The magnetic flux in a closed circuit of resistance 20 Ω varies with time t as ϕ=4t3+2t215t+3. Calculate the induced emf at t = 1s

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a

-1 V

b

2 V

c

4 V

d

1 V

answer is C.

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Detailed Solution

Given : Resistance = 20Ω;ϕ=4t3+2t215t+3
Required equation ε=/dt
ε=ddt4t3+2t215t+3dt=12t2+4t15
=124+15( sincet =1s)=1V
Therefore, the magnitude of induced emf is – 1 V

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