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The magnetic flux $ϕ$ (in weber) is a closed circuit of resistance $10 Ω$ varies with time t(in second) according to the equation $ϕ = 6 t^{2} - 5 t + 1$ . The magnitude of induced current at t=0.25sec in

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1.2A

0.8A

0.6A

0.2A

answer is D.

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Detailed Solution

$|e| = |\frac{d ϕ}{d t}| = 12 t - 5 = \frac{12}{4} - 5 = 2 V$

$i = \frac{e}{R} = \frac{2}{10} = 0.2 A$

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