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Q.

The magnetic induction at a point P which is at a distance of 4 cm from a long current-carrying wire is 10^-3 T. The field of induction at a distance of 12 cm from the current-carrying wire will be :

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a

9 x 10^-3 T

b

1.11 x 10^-4 T

c

3.33 x 10^-4 T

d

3 X 10^-3 T

answer is A.

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Detailed Solution

Magnetic field due to long current carrying wire= $\frac{μ_{o} i}{2 πd}$

Hence magnetic field at 12 cm becomes one third of the magnetic field at 4cm which becomes equal to 3.33X $10^{- 4}$

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