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The magnetic moment 2.84 BM as shown by
(atomic no Ni=28 ,Ti =22 ,Cr =24,Co=27)

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Ti⁺³

Cr⁺³

Co⁺²

Ni⁺²

answer is D.

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Detailed Solution

μ= $\sqrt{n (n + 2)}$ B.M.

But μeff=2.84 B.M.

Hence, 2.84= $\sqrt{n (n + 2)}$

2.84= $\sqrt{2 (2 + 2)}$ = $\sqrt{8}$
n=2

Ni²⁺ has 3d⁸ electronic configuration

Thus, it has 2 unpaired electrons.

Thus, magnetic moment 2.84 BM is given by Ni²⁺

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