The magnetic moment associated with a circular coil of $35$ turns and radius $10 cm$, if it carries a current of $20 A$ is

Given $N=35, r=10 cm=10\times {10}^{-2}m, I=20 A$

Then magnetic moment associated with this circular coil

$M=NIA=NI{\mathrm{\pi r}}^2=35\times 20\times \frac{22}{7}\times {\left(10\times {10}^{-2}\right)}^2=22 {\mathrm{Am}}^2$