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The magnetic moment of a circular loop is 2.1×10^–25 Am^2. Find magnetic field on the axis of loop at distance of 1A° from the loop

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4.2 × 10^–2 T

2.2 × 10^–2 T

3.2 × 10^–2 T

5.2 × 10^–2 T

answer is A.

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Detailed Solution

$\begin{array}{l} B_{\infty} = \frac{μ_{0}}{4 π} \frac{2 M}{r^{3}} \\ = \frac{10^{- 7} \times 2 \times 2 .1 \times 10^{- 25}}{{(10^{- 10})}^{3}} = 4 .2 \times 10^{- 2} T \end{array}$

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