The magnetic moment of a short bar magnet is 4Am². The magnetic induction on its axial line at a distance of 20 cm is

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10^–2T

10^–1T

10^–4T

10^–3T

answer is A.

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Detailed Solution

$B = \frac{μ_{0}}{4 π} \frac{2 M}{d^{3}} = \frac{10^{- 7} \times 2 \times 4}{{(20 \times 10^{- 2})}^{3}} = \frac{10^{- 7} \times 8}{8 \times 10^{- 3}} = 10^{- 4} T$

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