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The magnetic moment of M^x+ (Atomic number of M = 25) is $\sqrt{15}$ B.M. The number of unpaired electrons and the value of x respectively are

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4,3

3,4

3,2

5,2

answer is B.

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Detailed Solution

$\sqrt{n (n + 2)} = \sqrt{15}, n = 3$ ( n = number of unpaired electrons)
Therefore, x = 4
$∵ M^{4 +} = [Ar] 3 d^{3}$

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