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Q.

The magnetic moment produced in a substance of 1 g is $6 x 10^{- 7} {Am}^{2}$ . If its density is $5 g / {cm}^{3}$ , then the intensity of magnetisation in A/m will be

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a

$8.3 x 10^{6}$

b

3.0

c

$1.2 x 10^{- 7}$

d

$3 x 10^{- 6}$

answer is B.

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Detailed Solution

$I = \frac{M}{V} = \frac{M}{mass / density}$

Given mass = 1g = $10^{- 3} kg$

Density = $5 g / {cm}^{3} = \frac{5 x 10^{- 3} kg}{{(10^{- 2} m)}^{3}} = 5 x 10^{3} kg / m^{3}$

Hence, $I = \frac{6 x 10^{- 7} x 5 x 10^{3}}{10^{- 3}} = 3 A / m$

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