The magnetic moment value of species X is 4.8 B.M .Find out the number of unpaired electrons is X.

The magnetic moment value of species X is 4.8 B.M . So,

$\begin{array}{l}\sqrt{n(n+2)}=4.89\\ n(n+2)=(4.89{)}^2\\ n(n+2)=23.912\approx 24\end{array}$

In electronic configuration of this element, we get the 4 unpaired electron.