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Q.

The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 50 mA. This inductor is of inductance

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a

125 H

b

0.125 H

c

20 H

d

2 H

answer is D.

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Detailed Solution

U=12Li2

25×10-3=12L50×10-32

L=20H

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