The magnetic susceptibility of material of a rod is 599, permeability of vacuum is $4 π \times 10^{- 7} h e n r y / m$ . The absolute permeability of material of rod in herny/m is__

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$48 π \times 10^{- 5}$

$24 π \times 10^{- 5}$

$36 π \times 10^{- 5}$

$12 π \times 10^{- 5}$

answer is B.

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Detailed Solution

$M a g n e t i c S u s c e p t i b i l i t y, χ = μ_{r} - 1 \Rightarrow χ = \frac{μ}{μ_{0}} - 1$

$G i v e n : χ = 599$

$\Rightarrow 599 = \frac{μ}{4 π \times 10^{- 7}} - 1 \Rightarrow \frac{μ}{4 π \times 10^{- 7}} = 600$

$\Rightarrow μ = 600 \times 4 π \times 10^{- 5} \Rightarrow μ = 24 \times 10^{- 5} π μ = 24 π \times 10^{- 5} h e n r y / m$

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