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Q.

The magnification ‘m’, the image distance ‘v’ and focal length ‘f’ of a spherical mirror are related as

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a

$m = \frac{+ f}{v - f}$

b

$m = \frac{f}{f - v}$

c

$m = \frac{f - v}{f}$

d

$m = \frac{f + v}{f}$

answer is A.

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Detailed Solution

$\frac{1}{f} = \frac{1}{u} + \frac{1}{v}$

$m = \frac{- v}{u}$

$- m = \frac{v}{u}$

$\frac{v}{f} = \frac{v}{u} + \frac{v}{v}$

$\frac{v}{f} = - m + 1$

$m = 1 - \frac{v}{f}$

$m = \frac{f - v}{f}$

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