The magnifying power of a microscope with an objective of 5 mm focal length is 400. The length of its tube is 20 cm. Then the focal length of the eye-piece is

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160 cm

200 cm

2.5 cm

0.1 cm

answer is C.

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Detailed Solution

If nothing is said then it is considered that final image is formed at infinite and $m = \frac{LD}{f_{o} f_{e}} \Rightarrow 400 = \frac{20 \times 25}{0 .5 \times f_{e}} \Rightarrow f_{e} = 2 .5 cm$

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